Evaluate the cumulative distribution function of an RevWeibull distribution
Source:R/ReversedWeibull.R
cdf.RevWeibull.RdEvaluate the cumulative distribution function of an RevWeibull distribution
Usage
# S3 method for class 'RevWeibull'
cdf(d, x, drop = TRUE, elementwise = NULL, ...)Arguments
- d
A
RevWeibullobject created by a call toRevWeibull().- x
A vector of elements whose cumulative probabilities you would like to determine given the distribution
d.- drop
logical. Should the result be simplified to a vector if possible?
- elementwise
logical. Should each distribution in
dbe evaluated at all elements ofx(elementwise = FALSE, yielding a matrix)? Or, ifdandxhave the same length, should the evaluation be done element by element (elementwise = TRUE, yielding a vector)? The default ofNULLmeans thatelementwise = TRUEis used if the lengths match and otherwiseelementwise = FALSEis used.- ...
Arguments to be passed to
pgev. Unevaluated arguments will generate a warning to catch mispellings or other possible errors.
Value
In case of a single distribution object, either a numeric
vector of length probs (if drop = TRUE, default) or a matrix with
length(x) columns (if drop = FALSE). In case of a vectorized distribution
object, a matrix with length(x) columns containing all possible combinations.
Examples
set.seed(27)
X <- RevWeibull(1, 2)
X
#> [1] "RevWeibull(location = 1, scale = 2, shape = 1)"
random(X, 10)
#> [1] 0.9426871 -3.9596589 0.7303525 -1.2219891 -2.0076752 -0.8243573
#> [7] -4.2483783 -11.0231439 -2.9741769 -2.3014673
pdf(X, 0.7)
#> [1] 0.430354
log_pdf(X, 0.7)
#> [1] -0.8431472
cdf(X, 0.7)
#> [1] 0.860708
quantile(X, 0.7)
#> [1] 0.2866501
cdf(X, quantile(X, 0.7))
#> [1] 0.7
quantile(X, cdf(X, 0.7))
#> [1] 0.7